Abby’s Guide > Outdoor Power Equipment (Lawn Mowers, Snow Blowers, Chain Saws and more) > Discussions > Single stage output velocity
Outdoor Power Equipment (Lawn Mowers, Snow Blowers, Chain Saws and more) Discussions |
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trouts2
Location: Marlboro MA
Joined: Dec 8, 2007
Points: 1328
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Single stage output velocity
Original Message Jan 31, 2012 7:27 pm |
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Horizontal lists don't usually post correctly so the info below..... Make...............Engine RPM,,,,,,Auger dia........Auger RPM................Velocity out ft/min Powerlite, .........4000....................7........................1550..............................2840 Murray 3ph........4100..................8 1/4....................1025..............................2213 Maco 3hp...........4100..................8 1/4....................980...............................2116 Borat....................6000.................8 1/4...................1470.............................3173 Toro 350..............4200.................8 1/2.....................xxxxx..............................xxxxx Borat, Your auger RPM was approximated from Maco's. Different belts but likely both pulley diameters are the same or very close. The estimate was 245 RPM per 1K engine RPM. It would be interesting to compare impeller bearings. Murray and Maco both have roller bearings in the drive side of the auger shaft, flange on the other. Borat your's is probably the same. I'd have to check the Toro but I think flange on both sides. The velocity out of a dual stage is 3400 to 4000 ft/min most common around 3700-3800 ft/min (that is if I am remembering those numbers right). The better brands of machines will all be at the top of the high end. Those numbers seem about right given what a Powerlite can do versus a dual stage in the back yard in conditions good for the Powerlite.
This message was modified Feb 1, 2012 by trouts2
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RedOctobyr
Location: Lowell area, MA
Joined: Nov 5, 2011
Points: 282
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Re: Single stage output velocity
Reply #6 Feb 1, 2012 10:29 am |
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Red, 66.9 ft/sec out can’t be right. That’s 4014 ft/min. You speed is 2155 ft/min if 47.9 ft/sec is right for your impeller.
Are we all talking about the same thing? Output speed = velocity output = impeller (or paddle) tip speed, correct? Whether ft/sec, ft/min, or mph (or kph, for borat & co.), we're all describing the same thing. Since at least personally I'm more familiar with mph, 47.9 ft/sec is 32.6 mph, to put it more commonly-used units. My 2-stage, at 57.6 ft/sec is 39.2 mph. Those sound reasonable to me. I wouldn't expect it to be 200 mph or something. The 66.9 ft/sec number in my list was for taking my SS from 4300 RPM to 6000 RPM (boratifying it). So that's hardly a stock number, but I don't see any reason to doubt it. If the 47.9 ft/sec is correct (and it's just going through the math), then the 66.9 is just scaling up by the engine speed. Unless I'm misunderstand what you mean? And aa335, these hardly tell the whole story. Like you said, they'll give you an indication of relative throwing distances with lightweight snow (and still does not consider chute shape or any of that stuff). Snow that will still let the engine hold it's governed RPM. Once you start to bog the engine down, all bets are off. An 11hp 2-stage monster with a 50 ft/sec impeller tip speed might actually be able to maintain that tip speed, even going through 8" of wet heavy stuff. A 3hp SS even ramped up to 60 ft/sec will be just about stalled out in that same snow I have thought in the past that it would be cool if you could crank up your auger & impeller on a 2-stage. There were a number of times with my MTD that it had the power to barrel through, say, a fluffy 4" storm. But the auger and impeller were not gathering & flinging fast enough to keep up with the forward speed I wanted. That's what we need next, folks, hydrostatic transmissions to adjust your effective gear ratio on the auger & impeller assembly
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aa335
Joined: Nov 29, 2008
Points: 2434
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Re: Single stage output velocity
Reply #7 Feb 1, 2012 10:43 am |
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RedOctobyr, I'm pretty sure my 11hp 2 stage even at half throttle will out throw any of these high velocity SS when the snow condition is right. If you want hydro, you have to buy a Honda or certain Husqvarna-built snowblowers (aka Craftsman). Honda even went a step further, packing dual electric motors powering the tractor section, without robbing power from the engine to throw snow ($8000 hybrid). Anyways, a fast moving 250lbs snowblower catching a broken pavement coming to a sudden stop would probably cause an enthusiastic operator to have an uncomfortable endo. And I sure don't want any more controls to change gear ratios on auger / impeller, there are already enough levelers, knobs, cranks, pedals, to keep a seasoned helicopter pilot busy. :)
This message was modified Feb 1, 2012 by aa335
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RedOctobyr
Location: Lowell area, MA
Joined: Nov 5, 2011
Points: 282
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Re: Single stage output velocity
Reply #13 Feb 1, 2012 8:17 pm |
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hirschallan, you're probably right. And, from what trouts2 posted, the torque is already dropping off. The benefit would be that, even if you're past the torque peak, the impeller & auger will be spinning faster, and will better deal with lightweight snow. They'll fling more, and further. And as the engine loads up, it will slow down anyhow, more towards the normal operating speed. trouts2, I like that idea, of adjusting full throttle to be past 3600, for when you need just a bit more. Then just drop the throttle slightly for normal operation. Simple yet clever I updated my numbers, to change everything to ft/min, from ft/sec. I also added a column which might begin to address aa335's point about the weight of the snow. I took the engine's RPM and rated HP, and calculated engine torque from that. Then factored in the torque multiplication factor from engine RPM vs impeller/paddle RPM, and also the impeller/paddle diameter. So it shows the torque on the impeller/paddle, as well as the corresponding available force at the tip of the impeller/paddle (which considers the diameter of the impeller/paddle). This is really only "useful" in comparing machines of the same type, SS or 2-stage. And "useful" is probably too strong a word. It completely ignores power being used actually turning the augers themselves (on a 2-stage) and driving the wheels, in addition to other losses. It was more just for curiosity, and to get a relative understanding of how well the impeller/paddle would deal with heavier snow. The "Impeller tip force" would relate best to heavy snow performance, in my opinion. It's worth the paper it's printed on, as long as you don't print it
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trouts2
Location: Marlboro MA
Joined: Dec 8, 2007
Points: 1328
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Re: Single stage output velocity
Reply #14 Feb 2, 2012 8:16 am |
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Red, A few questions for you. >>>I took the engine's RPM and rated HP, and calculated engine torque from that. Makers usually give a Max torque at some rpm and that is usually below max torque say 24-2800 on a 3600 engine. If you take max rpm and the makers max torque that won’t be the same as the makers max torque as they spec max at some rpm lower than max. At least that’s what I’ve always seen. Also, I think hp figures are at max rpm not at max torque rpm. Since torque drops off faster and faster after max heading to 3600 and those curves vary from engine to engine then using max at 3600 can’t be done. It’s non-linear and rate of torque drop off different from engine to engine. I suppose it’s a pickle for makers. If they gave ratings at 3600 people could compare levels vs makers given max torque at 24, 25, 2600…& etc. But that would not give you max which is good to know for apps where the engine sags under load into it’s power torque range like in snowblowers. In the past I’ve looked at trying to figure out what the torque curve would be for a pushed engine and was unable to come up anything. If you have a makers published power curve then OK but most don’t give them. If the above is right then it would make the impeller torque and lb force figures iffy. But the force figure is interesting as lb’s are sort of familiar. Is that something like the force available would lift that amount one foot? Just say the torque figures are off but are a rough ball park. If they are close enough then useful even if inaccurate. It’s a little more understandable to compare lbs than torque numbers. Then factored in the torque multiplication factor from engine RPM vs impeller/paddle RPM, and also the impeller/paddle diameter. So it shows the torque on the impeller/paddle, as well as the corresponding available force at the tip of the impeller/paddle (which considers the diameter of the impeller/paddle). This is really only "useful" in comparing machines of the same type, SS or 2-stage. And "useful" is probably too strong a word. As mentioned before, as a side issue when thinking about this stuff it’s one thing to have the numbers but the total design implementation factors in. Once you have the get force there’s the design of the barrel, the impeller arm count, the shape of the impeller arms, shape of the bucket outlet hole, chute shape and a many more. Over the years other than chute shape a have not made much progress on understanding the other parts especially the shape of the impeller arms. It’s pretty much black magic but basic to is all is the umph has be there. Nice chart. If the chart is in excel and you don’t mind please send me a copy, trouts2@gmail.com
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RedOctobyr
Location: Lowell area, MA
Joined: Nov 5, 2011
Points: 282
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Re: Single stage output velocity
Reply #15 Feb 2, 2012 9:31 am |
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Makers usually give a Max torque at some rpm and that is usually below max torque say 24-2800 on a 3600 engine. <snip>
If the above is right then it would make the impeller torque and lb force figures iffy. But the force figure is interesting as lb’s are sort of familiar. Is that something like the force available would lift that amount one foot? Just say the torque figures are off but are a rough ball park. If they are close enough then useful even if inaccurate. It’s a little more understandable to compare lbs than torque numbers. Then factored in the torque multiplication factor from engine RPM vs impeller/paddle RPM, and also the impeller/paddle diameter. So it shows the torque on the impeller/paddle, as well as the corresponding available force at the tip of the impeller/paddle (which considers the diameter of the impeller/paddle). This is really only "useful" in comparing machines of the same type, SS or 2-stage. And "useful" is probably too strong a word. As mentioned before, as a side issue when thinking about this stuff it’s one thing to have the numbers but the total design implementation factors in. Once you have the get force there’s the design of the barrel, the impeller arm count, the shape of the impeller arms, shape of the bucket outlet hole, chute shape and a many more. Over the years other than chute shape a have not made much progress on understanding the other parts especially the shape of the impeller arms. It’s pretty much black magic but basic to is all is the umph has be there. Nice chart. If the chart is in excel and you don’t mind please send me a copy, trouts2@gmail.com "Makers usually give a Max torque at some rpm and that is usually below max torque say 24-2800 on a 3600 engine."You're right. However, I made no effort to use manufacturer's torque numbers (which are typically harder to find for older, hp-rated engines anyhow). If we assume that the horsepower of the engine is rated based on the operating speed (a fair assumption), then this works better. You can calculate torque if you know hp and RPM, which is what I did, for the operating speeds listed. Now, in the case of the SS322, the operating speed is 4300, not 3600. I don't know which speed the 3hp is based on. But I used the 4300, for discussion purposes. You're right that the torque is definitely a curve, so this number doesn't exactly tell the whole story. But there are so many other assumptions involved in this anyhow that it almost doesn't matter I have come across a torque/power curve plot for at least 1 engine, I'd have to look later and see if I saved it. " But the force figure is interesting as lb’s are sort of familiar. Is that something like the force available would lift that amount one foot? "
Torque is commonly listed in ft-lb (well, lb-ft, really, but that's kind of semantics). A torque of 5 ft-lb can apply a force of 5 lbs (can lift 5 lbs), at a radius of 1 ft. Or 2.5 lbs at a radius of 2 ft. So, in the example of the ST824, the impeller has a 12" diameter, or 6" radius (0.5 ft). So the maximum force at the tip is torque/radius, or 38.2 ft-lb / 0.5 ft, or 76.4 lb.
So given the same torque on a 12" diameter impeller vs an 8" diameter impeller, the max tip force will be greater on the smaller-diameter, 8" impeller. It will slow down less with heavy snow. But it also won't be throwing as far.
Like you said, there are a ton of other factors too. And the impeller/paddle is doing more than just flinging snow out, it's also moving the new snow to the center. And for a 2-stage, the augers are also sucking up power, and the transmission, etc. This is just a potentially-interesting exercise in comparing similarly-designed machines, at best.
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